experiment2 acid base reactions

experiment2 acid base reactions - Part 1- Solubility with a...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Part 1- Solubility with a Non-Polar Solvent The solvent used was hexane, a non-polar molecule, meaning it can only dissolve through Induced Dipole/Induced Dipole interactions. Because like dissolves like, the solutes can all be dissolved as they all have non-polar sections. Part 2- Solute Miscibility with a Polar Solvent Although several of the solutes have polar parts, they are not strong enough to cancel out hydrogen bonds made by H 2 O. This made two layers of compounds form in the test tubes. Tubes 4 and 5 had a different result explained in part 3. Part 3- Water Solubility of Alcohols Using only Alcohols in this experiment, the size of the molecules made the difference in the solubility. The larger molecules have larger non-polar parts, making them the hardest to dissolve in water because polar and non-polar molecules do not mix well (like dissolves like). The alcohols used Dipole-Dipole interactions to mix. Part 4- Temperature Dependence of Solubility Benzoic Acid uses Dipole-Dipole interactions to form a solid state but they are not strong enough to break the hydrogen bonds in water, explaining the chunks of Benzoic Acid on the bottom of the tube before heating. When heated, enough energy was added to break the bonds and melt the acid, allowing it to dissolve in water. After the solution was taken out of the heat and allowed to cool, the Acid was allowed to reform into a white crystal-like structure.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Part 5- The solubility of an Acid Benzoic Acid is unable to break the intermolecular forces in water, explaining the separate layers before any acid was added. When NaOH/NH 4 OH 2 was added, ions were produced from a reaction. The ions create H 2 O molecules, making mixed solutions. NaHCO 3 partially reacts with the acid so it cannot form bonds with water to completely dissolve. Bonds that were made created higher tension making the acid float. When HCl was added
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 8

experiment2 acid base reactions - Part 1- Solubility with a...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online