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Unformatted text preview: B ) c ] = 1. 8 = 0 . 2 1.4.2: Pick a light bulb at random. Let D be the event (the light bulb is defective), and B be the event ( the light bulb is made in city B). Then P ( B ) = 1 / 3 ,P ( D  B ) = . 01, and P ( D c B ) = P ( D c  B ) P ( B ) = [1P ( D  B )] P ( B ) = 0 . 99 × 1 / 3 = 0 . 33 1.4.3: P ( rain tomorrow  rain today ) = P ( rain today and tomorrow ) P ( rain today ) = . 3 . 4 = 3 / 4 1.4.4: Call the events A(having probability 0.1) and B(having probability 0.3). a) P ( A c B c ) = P ( A c B c ) = 0 . 9 × . 7 = 0 . 63 b) 1P ( A c B c ) = 0 . 37 c) P ( AB c ∪ A c B ) = P ( AB c ) + P ( A c B ) = 0 . 1 × . 7 + 0 . 9 × . 3 = 0 . 34...
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This note was uploaded on 09/14/2009 for the course STAT 134 taught by Professor Aldous during the Fall '03 term at Berkeley.
 Fall '03
 aldous

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