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Unformatted text preview: P Z ≤ = 1 – 0.8413 = 0.1587 Thus, the expected number of students that are greater than 6 feet tall = 1200*0.1587 = 190.44 = 191 b) Also, P[Height of a Student is between 5 feet and 6 feet] = P[Height of a Student is between 60 inches and 72 inches] = P [ 60 < X < 72] = 60 67 67 72 67 5 5 5 X P < < = P [ 1.4 < Z < 1] = P [ Z < 1] – P [ Z < 1.4] = 0.8413 – 0.0808 = 0.7605 Thus, the expected number of students that are between 5 feet and 6 feet = 1200*0.7605 = 912.6 = 913 Note that using MS Excel P[Z<a] can be calculated using the Excel formula =NORMSDIST(a)...
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 Spring '08
 LaniS
 Normal Distribution, Cauchy distribution, 6 feet, 5 feet, 5 inches, 7 Inches

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