Experiment 14 - Change in heat per mole of H and OH ions...

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Experiment 14: Heat Effects and Calorimetry By: Daniel Fore Drew Hutchison CH1211-11 Yulin Wang 12:30pm - 03:20pm Tuesday October 30, 2007
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Data and Calculations: Heat Effects and Calorimetry A. Specific Heat Trial 1 Trial 2 (3)Mass of stoppered test tube plus metal (4)Mass of test tube and stopper (1)Mass of calorimeter (2)Mass of calorimeter and water (8)Mass of water (2) – (1) = (10)Mass of metal (3) – (4) = (6)Initial temp of water in calorimeter (7)Initial temp of metal (5)Equilibrium temp of metal and water in calorimeter (9)Change in temp of water (5) – (6) = (11)Change in temp of metal (5) – (7) = qH2O 4.18 * (8) * (9) = Specific heat of the metal 552.914=-5*(10)*(11) Approx. molar mass of metal 25/.4214 Unknown no. Unknown identity C. Heat of Neutralization Original temp of HCL solution Original temp of NaOH solution avg=24.55 Final temp of Neutralized mixture Change in temp 30.8-24.55 qH2O 4.184*50*6.25
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Change in heat for the neutralization reaction
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Unformatted text preview: Change in heat per mole of H+ and OH- ions reacting 1307.5/.025 B. Determination of the Molar Mass of an Unknown Acid Mass of vial plus contents 79.569g Test 1 Test 2 Initial reading, NaOH buret 17.5mL 26.9mL Final reading, NaOH buret 26.9mL 36.4mL Processing the Data A. Standardization of NaOH Solution Trial 1 Trial 2 Total volume NaOH 8.9mL 8.6mL Molarity, M, of standardized HCL 0.1M Molarity, M, in standardized HCL 0.1M By Equation 3, .1*25/8.9 .1*25/8.6 Trial1 Trial 2 M OH .2809M .2907M Average molarity of NaOH solution, M .2858M B. Determination of the Molar Mass of the Unknown Acid Trial 1 Trial 2 Mass of sample .504g .503g Volume NaOH used 9.4mL 9.5mL (1)No. moles NaOH=(V*M)/1000 (9.4*.2858)/1000 .0027M .0027M (9.5*.2858)/1000 No. moles H+ in sample---same as (1) .0027M .0027M MM=(no. grams acid)/(no. moles H+) .504/.0027 186.67g .503/.0026186.3g Unknown no. _B_...
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Experiment 14 - Change in heat per mole of H and OH ions...

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