Lecture 3 - For sodium: E Na = (58/+1) log (450/50) = 58...

Info iconThis preview shows pages 1–21. Sign up to view the full content.

View Full Document Right Arrow Icon
Nernst equation: E I = (RT/zF) ln ([I o ]/[I i ]) Converted for constants and room temperature to log base 10, answer will be in mV: E I = (58/z) log ([I o ]/[I i ])
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
For potassium: E K = (58/+1) log (20/400) = 58 log (1/20) = -58 log 20 = -58 (1.3) = -75 mV
Background image of page 2
For potassium: E K = (58/+1) log (20/400) = 58 log (1/20) = -58 log 20 = -58 (1.3) = -75 mV
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
For sodium: E Na = (58/+1) log (450/50) = 58 log (9) = +55 mV For chloride: E Cl = (58/-1) log (560/40) = -58 log (14) = -67 mV
Background image of page 4
2.7 Evidence that the resting potential is determined by K + concentration gradient.
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
For potassium: E K = (58/+1) log (20/400) = 58 log (1/20) = -58 log 20 = -58 (1.3) = -75 mV
Background image of page 6
2.7 Evidence that the resting potential is determined by K + concentration gradient.
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 12
Background image of page 13

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 14
Background image of page 15

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 16
Background image of page 17

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 18
Background image of page 19

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 20
Background image of page 21
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: For sodium: E Na = (58/+1) log (450/50) = 58 log (9) = +55 mV For chloride: E Cl = (58/-1) log (560/40) =-58 log (14) = -67 mV A current flows in response to closing the switch. Current is constant. Current measured in units called amperes (1coulomb/sec). The relationship of current and voltage is dictated by Ohms law, V=IR Resistance is measured in units called ohms In Neurobiology we often use the inverse of resistance, called conductance, i.e. V=I/g; units here are siemens. V R = IR V C = V B (1-e-tau/RC ) 2.8 The role of sodium in the generation of an action potential. (Part 1) 2.8 The role of sodium in the generation of an action potential. (Part 2)...
View Full Document

Page1 / 21

Lecture 3 - For sodium: E Na = (58/+1) log (450/50) = 58...

This preview shows document pages 1 - 21. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online