4 - kavo (ak22862) HW04 Janow (12121) 1 This print-out...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: kavo (ak22862) HW04 Janow (12121) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points An electric field of magnitude 5290 N / C is applied along the x axis. Calculate the electric flux through a rect- angular plane 0 . 3 m wide and 1 . 04 m long if the plane is parallel to the yz plane. Correct answer: 1650 . 48 N m 2 / C. Explanation: Let : E = 5290 N / C , = 0 , L = 1 . 04 m , and W = 0 . 3 m . The area of the rectangle is A = LW = (1 . 04 m) (0 . 3 m) = 0 . 312 m 2 . Since the field is uniform,the flux is = E A = E A cos = (5290 N / C) (0 . 312 m 2 ) (cos0 ) = 1650 . 48 N m 2 / C . 002 (part 2 of 3) 10.0 points Calculate the electric flux through the same rectangle, if it is parallel to the xy plane. Correct answer: 0 N m 2 / C. Explanation: The angle is = 90 ,cos = 0 , and = E A = E A cos = (5290 N / C) (0 . 312 m 2 ) (0) = 0 N m 2 / C . 003 (part 3 of 3) 10.0 points Calculate the electric flux through the same rectangle, but now the rectangle contains the y axis and its normal makes an angle of 18 with the x axis. Correct answer: 1569 . 7 N m 2 / C. Explanation: Let = 18 = E A = E A cos = (5290 N / C) (0 . 312 m 2 ) (cos18 ) = 1569 . 7 N m 2 / C . 004 10.0 points The net electric flux through a closed surface is 1. infinite only if the net charge enclosed by the surface if zero. 2. zero if the net charge enclosed by the surface is zero. correct 3. zero if only negative charges are enclosed by the surface. 4. infinite only if there are no charges en- closed by the surface. 5. zero if only positive charges are enclosed by the surface. Explanation: Gausss law tells us the net electric flux through a closed surface is integraldisplay s vector E d vector A = Q . So the net flux is zero only if the net charge enclosed is also zero....
View Full Document

Page1 / 5

4 - kavo (ak22862) HW04 Janow (12121) 1 This print-out...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online