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Unformatted text preview: kavo (ak22862) HW04 Janow (12121) 1 This printout should have 18 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points An electric field of magnitude 5290 N / C is applied along the x axis. Calculate the electric flux through a rect angular plane 0 . 3 m wide and 1 . 04 m long if the plane is parallel to the yz plane. Correct answer: 1650 . 48 N m 2 / C. Explanation: Let : E = 5290 N / C , = 0 , L = 1 . 04 m , and W = 0 . 3 m . The area of the rectangle is A = LW = (1 . 04 m) (0 . 3 m) = 0 . 312 m 2 . Since the field is uniform,the flux is = E A = E A cos = (5290 N / C) (0 . 312 m 2 ) (cos0 ) = 1650 . 48 N m 2 / C . 002 (part 2 of 3) 10.0 points Calculate the electric flux through the same rectangle, if it is parallel to the xy plane. Correct answer: 0 N m 2 / C. Explanation: The angle is = 90 ,cos = 0 , and = E A = E A cos = (5290 N / C) (0 . 312 m 2 ) (0) = 0 N m 2 / C . 003 (part 3 of 3) 10.0 points Calculate the electric flux through the same rectangle, but now the rectangle contains the y axis and its normal makes an angle of 18 with the x axis. Correct answer: 1569 . 7 N m 2 / C. Explanation: Let = 18 = E A = E A cos = (5290 N / C) (0 . 312 m 2 ) (cos18 ) = 1569 . 7 N m 2 / C . 004 10.0 points The net electric flux through a closed surface is 1. infinite only if the net charge enclosed by the surface if zero. 2. zero if the net charge enclosed by the surface is zero. correct 3. zero if only negative charges are enclosed by the surface. 4. infinite only if there are no charges en closed by the surface. 5. zero if only positive charges are enclosed by the surface. Explanation: Gausss law tells us the net electric flux through a closed surface is integraldisplay s vector E d vector A = Q . So the net flux is zero only if the net charge enclosed is also zero....
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 Fall '08
 Opyrchal
 Physics

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