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Unformatted text preview: kavo (ak22862) HW13 Janow (12121) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 15.0 points An LC circuit is shown in the figure below. The 28 pF capacitor is initially charged by the 7 V battery when S is at position a . Then S is thrown to position b so that the capacitor is shorted across the 14 mH inductor. 14 mH 28 pF 7 V S b a What is the maximum value for the oscil lating current assuming no resistance in the circuit? Correct answer: 0 . 00031305 A. Explanation: Let : C = 28 pF = 2 . 8 10 11 F , L = 14 mH = 0 . 014 H , and E = 7 V . The maximum charge on the capacitor is Q max = C V . The maximum current is I max = Q m = C V , where is the oscillatory frequency given by = 1 LC . Thus I max = radicalbigg C L V = radicalbigg 2 . 8 10 11 F . 014 H (7 V) = . 00031305 A . 002 (part 2 of 3) 10.0 points What is the natural angular frequency of the circuit? Correct answer: 1 . 59719 10 6 rad / s. Explanation: = 1 LC = 1 radicalbig (0 . 014 H) (2 . 8 10 11 F) = 1 . 59719 10 6 rad / s . 003 (part 3 of 3) 10.0 points What is the maximum energy stored in the magnetic field of the inductor? Correct answer: 6 . 86 10 10 J. Explanation: U max,ind = U max,cap = Q 2 max 2 C = 1 2 C V 2 ....
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This note was uploaded on 09/16/2009 for the course PHYS 121 taught by Professor Opyrchal during the Fall '08 term at NJIT.
 Fall '08
 Opyrchal
 Physics

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