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Unformatted text preview: AAE3 52
Homework Set #10
Due 19 November 2008 (one day before the test) Problem 101 a) b) 0) The cross—section shown has a 1000 lb. Fl
resultant shear load applied to it. Use the
concept of resultant forces and moments to solve for the horizontal location of the _ 6”
shear center. G is constant. _ " ‘ I? .
For the same section and loading, let G ‘ _ 0‘ L
for the upper web be twice the value of z . ‘ the other two webs and repeat the
calculations in part a. Find the effective torsional stiffness for
parts (a) and (b). Problem 102 3) 19) Determine the shear ﬂow distribution in the thinwall beam crosssection
shown when the 1000 lb. force is
applied at the shear center. Find the horizontal location of the
shear center from the lower right hand
stringer. Compute the effective
stiffness if G=4x1 06 psi. torsional Problem 10—2 $003.3? 152532 f , = 152.07“ um T}?
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. 163: z 91‘ 9L? J“ (gal)? (45%” = 1000 Q, Q‘ % 1 ' [ooo /02
———— Q"! L A
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M Fun3W 1 azw” I
.. G 0 a ’32 +Az~loJ
GM ‘9'” f) i
Z} 53—: 660,4 A?
2/ JAP Q40" ﬂgum NP: gm“ : £29362”
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 :,40A Q=20A @ :FM (Ci) ANNE w toWuLT—bb HIT. gar3’“ $07; qu 115 T a” ma use the concept of force and moment equivalence to find the shear f10ws
in the section shown. Why can't we use this approach in a1] prob?ems?t Both stringer areas are equa1. There are two webs. I I vRoBLEM ﬁﬁo C+§M6M CﬁWWa‘WU—JCSum about PM a.) I 2%9‘ = QOOOODCS') _ 1‘:  80000 ‘
Q )(3qu + 12°) ...
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 Spring '08
 Chen

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