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Unformatted text preview: prestage wait for uniform 5, 1 min move into Q stage move into Q scan use R scan for uniform 8, 4 min send to die end 4. (a) i time in system( i ) / 6 = 218 / 6 = 36 . 33. (b) Let X ( t ) be the number of entities in the system at time t . Area under sample path of X ( t ) Time 6th customer leaves = 218 100 = 2 . 18 . (c) 1. (d) The queue length at time t is Q ( t ) = max { X ( t )1 , } . The answer is 1 100 100 Q ( t ) dt = 1 . 18. (e) Entity i starts service when entity i1 leaves the system. Since we have the departure times, we can obtain the service times by subtracting the service initiation times from the departure times. The answer is 102 / 6 = 16 . 67....
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This note was uploaded on 09/17/2009 for the course ISYE 3044 taught by Professor Alexopoulos during the Spring '08 term at Georgia Institute of Technology.
 Spring '08
 ALEXOPOULOS

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