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Unformatted text preview: E i = 10, the following table is generated: Interval O i ( O iE i ) 2 /E i (0110) 9 0.1 (1120) 9 0.1 (2130) 9 0.1 (3140) 6 1.6 (4150) 17 4.9 (5160) 5 2.5 (6170) 10 0.0 (7180) 12 0.4 (8190) 7 0.9 (9100) 16 3.6 100 14 . 2 = χ 2 3 From Table A.6, χ 2 . 05 , 9 = 16 . 9. Since χ 2 < χ . 05 , 9 , then the null hypothesis of no di±erence between the sample distribution and the uniform distribution is not rejected. 7.10 X 1 = [7 × 37 + 29] mod 100 = 88 and R 1 = . 88. X 2 = [7 × 88 + 29] mod 100 = 45 and R 2 = . 45. X 3 = [7 × 45 + 29] mod 100 = 44 and R 3 = . 44....
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This note was uploaded on 09/17/2009 for the course ISYE 3044 taught by Professor Alexopoulos during the Spring '08 term at Georgia Institute of Technology.
 Spring '08
 ALEXOPOULOS

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