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Problem_set_5_new

# Problem_set_5_new - Problem Set 5 Evolution 1 Below are...

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Problem Set 5 Evolution 1. Below are some data for oyster viability based on their genotypes at the catalase locus. AA AB BB Total Zygotes 140 353 229 722 Adults 14 346 200 560 Assuming that only viability selection is occurring: A. Calculate the relative fitnesses of each genotype, setting w AA = 1. Which genotype has the highest fitness? B. Calculate the average excess of each allele. C. What do these average excess values tell you about the course of natural selection. Answers: A. First calculate the absolute fitnesses. Because only viability selection is occurring, these fitnesses are equal to the probability of surviving to adulthood for each genotype. So Absolute w AA = 14/140 = .10 w AB = 346/353 = .98 w BB = 200/229 = .87 To make these relative fitnesses, divide them all by w AA : Relative w AA = .10/.10 = 1 w AB = .98/.10 = 9.8 w BB = .87/.10 = 8.7 B . For this, you need the allele frequencies before selection and W, the average population fitness. p=140/722 + ½ 353/722 = .1939 + .2445 = .4384 = .44 q=229/722 + ½ 353/722 = .3172 + .2445 = .5617 = .56 W = .44 2 (1) + 2(.44)(.56)(9.8) + .56
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