03-01 Chap Gere

# 03-01 Chap Gere - 3 Torsion Torsional Deformations Problem...

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SECTION 3.2 Torsional Deformations 183 Solution 3.2-4 Circular steel tube L 5 0.90 m r 1 5 40 mm (a) S HEAR STRAIN AT INNER SURFACE From Eq. (3-5b): g 1 5 388 3 10 2 6 rad g min 5 g 1 5 r 1 f L 5 (40 mm)(0.008727 rad) 900 mm g max 5 0.0005 rad 5 0.008727 rad f 5 0.5 85 (0.5 8 ) ¢ p 180 rad degree (b) M AXIMUM OUTER RADIUS From Eq. (3-5a): ( r 2 ) max 5 51.6 mm ( r 2 ) max 5 (0.0005 rad)(900 mm) 0.008727 rad r 2 5 g max L f g max 5 g 2 5 r 2 f L ; r 1 r 2 Problem 3.2-5 Solve the preceding problem if the length L 5 50 in., the inner radius r 1 5 1.5 in., the angle of twist is 0.6°, and the allowable shear strain is 0.0004 rad.

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## This note was uploaded on 09/19/2009 for the course CEE 372 taught by Professor Siddharthan during the Spring '08 term at Nevada.

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03-01 Chap Gere - 3 Torsion Torsional Deformations Problem...

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