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sec 2.1 - SS'~~l(~"tLvLJ Qv No u-C ~ ~'2'L ~ o S"...

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.~. \ "((l . dy 2. - = e -O.Olxy2 dx (a) y(-6)=0 (c) y(O) = -4 (b) y(O) = 1 (d) y(8) = -4 dv 4.-' = (sin x) cas y ',-.4X (a) v(O) = 1 (c) v(3)=3 (b) v(1) = 0 (d) y(O) = -~ y 8 4 -4 -8 -8 -4 y 4 8 ) 4 -4 -2 2 4 FIGURE 2.11 Direction field for Problem 2 FIGURE 2.13 Direction field for Problem 4 c!'\ (-Cb.iO) 01\ (0 I \) 01\ ( t, 00.) ~ ) 0. So. 'j \.'-'\.c... 6 c-Vx:>o ~ 0 \.j -1.1\.c.. . ~ <0 lj eke. o \> S~.~·. ':>~\,,~ l ; s 0... S '-1 M. p. S'~\o ~ c. ?: O.f \
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~ cf-Ix =- lj C L-~X Y- - j). \j<'O: ~ <.0 j c4c.. 'Z- " ~ '>0 'j t4L. <0 ':1 cl.u 4- '~'j , ~ >0 Y tV\.L Y- ~ VJ\s~\nlc ? {s C\.) '1 ~p. s~~lL c,~: I I - 7- D L cJ, L, 7 C\r..L ~ S'1 Mf, S'19..~~ , 0.':;-' I') VA 5"u..~LL.
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