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Unformatted text preview: Math 330 Homework 4.2 (Pages 234,235) (6) Find an explicit description of Nul A , by listing vectors that span the null space. A = 1 5 4 3 1 0 1 2 1 0 0 SOLUTION: We perform row operations in order to solve Avectorx = vector 0. Note that since the matrix is already in Echelon form, we continue to get reduced Echelon form. R 1 ← R 1 5 R 2 = ⇒ 1 0 6 8 1 0 1 2 1 0 0 = ⇒ x 1 = 6 x 3 + 8 x 4 x 5 x 2 = 2 x 3 x 4 = ⇒ x 1 x 2 x 3 x 4 x 5 = x 3  6 2 1 5 + x 4 8 1 1 + x 5  1 1 So a basis for the Null space of A is  6 2 1 5 , 8 1 1 ,  1 1 (10) Show the given set is a vector space or find an example to the contrary:...
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This note was uploaded on 09/19/2009 for the course MATH 330 taught by Professor Johnson,j during the Spring '08 term at Nevada.
 Spring '08
 Johnson,J
 Math, Linear Algebra, Algebra, Vectors

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