Unformatted text preview: Math 330 Quiz 5.1 Friday April 3, 2009
The following matrix has 11 as an eigenvalue. Find the associated eigenspace. 12 1 3 A = 2 12 1 13 7 8 SOLUTION: 11 being an eigenvalue means that there is a nonzero x such that Ax = 11x (A  11I)x = 0 Which means finding x is equivalent to finding the null space of A  11I: 1 1 3 1 1 3 1 1 3 (R2,R3)(R22R1,R313R1) R2R2 = 0 1 7 2 1 1 0 1 7 0 6 42 0 6 42 13 7 3 1 0 4 1 1 3 R3R3+6R2 R1R1R2 = 0 1 7 = 0 1 7 0 0 0 0 0 0 x1 So we have that with x = x2 that x3 x1  4x3 x2 + 7x3 x1 = 4x3 4 x1 = 0 = x2 = 7x3 = x2 = x3 7 = 0 1 x3 = x3 x3 So our associated eigenspace of A for eigenvalue 11 is just Span 4 7 1 1 ...
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This note was uploaded on 09/19/2009 for the course MATH 330 taught by Professor Johnson,j during the Spring '08 term at Nevada.
 Spring '08
 Johnson,J
 Math, Linear Algebra, Algebra

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