chapter 4-5

chapter 4-5 - REDUCTION OF DISTRIBUTED LOADING (Section...

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Lecture Notes for Section 4.10 1 REDUCTION OF DISTRIBUTED LOADING (Section 4.10) Today’s Objectives : Students will be able to determine an equivalent force for a distributed load. In-Class Activities : Check homework, if any Reading quiz Applications Equivalent force Concept quiz Group problem solving Attention quiz READING QUIZ 1. The resultant force (F R ) due to a distributed load is equivalent to the _____ under the distributed loading curve, w = w(x). A) centroid B) arc length C) area D) volume 2. The line of action of the distributed load’s equivalent force passes through the ______ of the distributed load. A) centroid B) mid-point C) left edge D) right edge x w F R Distributed load curve
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Lecture Notes for Section 4.10 2 APPLICATIONS A distributed load on the beam exists due to the weight of the lumber. Is it possible to reduce this force system to a single force that will have the same external effect?
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This note was uploaded on 09/19/2009 for the course ME 241 taught by Professor Itani during the Spring '08 term at Nevada.

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chapter 4-5 - REDUCTION OF DISTRIBUTED LOADING (Section...

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