ME 242 Lecture 3 1.26

ME 242 Lecture 3 1.26 - ME 242 Dynamics January 26, 2009...

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1 ME 242 Dynamics January 26, 2009 Eric Wang Today’s Key Concepts Kinematics • Straight line motion • “Special Cases” 1. Acceleration is constant 2. Acceleration depends on position 3. Acceleration depends on speed Position • Position of Particle P relative to Point O O Velocity • Given the position: • By definition v P = d dt r P / O r P / O = x = ˙ x Strictly speaking: • Should use vectors • Not important for 1D motion, but important for 2D and 3D motion v P = d dt XYZ r P / O r P / O = xi = ˙ x i v P = d dt r P / O r P / O = x = ˙ x Acceleration • Position • Velocity • Acceleration v P = d dt r P / O = ˙ x r P / O = x a P = d dt v P = d 2 dt 2 r P / O = ˙ ˙ x
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2 Alternatively… Or ˙ x ( t 2 ) = ˙ x ( t 1 ) + ˙ ˙ x dt t 1 t 2 x ( t 2 ) = x ( t 1 ) + ˙ x dt t 1 t 2 v P ( t 2 ) = v P ( t 1 ) + a P dt t 1 t 2 r P / O ( t 2 ) = r P / O ( t 1 ) + v P dt t 1 t 2 Question: • Given x (0)= v (0)=0, what is x (2)? Solution:
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This note was uploaded on 09/19/2009 for the course ME 242 taught by Professor Kam during the Spring '06 term at Nevada.

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ME 242 Lecture 3 1.26 - ME 242 Dynamics January 26, 2009...

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