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ME 242 Lecture 4 1.28

ME 242 Lecture 4 1.28 - 1 ME 242 Dynamics Eric Wang...

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Unformatted text preview: 1 ME 242 Dynamics January 28, 2009 Eric Wang Today’s Key Concepts Cartesian Coordinates • 2D motion • Coordinate transformation array Position Vector r P / O = xi + y j Velocity v P = d dt XYZ r P / O = dx dt i + x d dt XYZ i + dy dt j + y d dt XYZ j + dz dt k + z d dt XYZ k r P / O = xi + y j + zk 3D Kinematics • Position • Velocity • Acceleration v P = d dt XYZ r P / O = ˙ x i + ˙ y j + ˙ z k a P = d dt XYZ v P = ˙ ˙ x i + ˙ ˙ y j + ˙ ˙ z k r P / O = xi + y j + zk Given: V =11.31 ft/s Find: η 2 Solution: V =11.31 m/s v x = v cos η v y = v sin η v x v y Final Position: tan30 = 0.97 x 1 x 1 = 1.68 ft x 1 = y 1 x = y = Constant Acceleration v x = 11.31cos η v y = 11.31sin η x = y = x 1 = 1.68 y 1 = 0.97 v 1 x 2 = v x 2 + 2 a x ( x 1 − x ) v 1 y 2 = v y 2 + 2 a y ( y 1 − y ) Constant Acceleration v x = v x + a x t x =...
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ME 242 Lecture 4 1.28 - 1 ME 242 Dynamics Eric Wang...

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