ME 242 Lecture 22 03.27

ME 242 Lecture 22 03.27 - ME 242 Dynamics March 27, 2009...

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1 ME 242 Dynamics March 27, 2009 Eric Wang Quiz #2 • 2 weeks from today • Will cover everything up to & including today’s lecture • Chapters 3, 4, & 5 (skip 5.3 & 5.4) • Closed book, closed notes • Cheat sheet (1 page, 1 side) • Starts at noon (not 12:05) Today’s Key Concepts Chapter 5: Multiparticle Systems Work-Energy Example Recall: Work-Energy For a single particle: KE 2 +PE 2 = KE 1 +PE 1 + W nc 1 2 KE = 1 2 mv 2 PE = F c ds W nc = F nc ds Multiparticle System Kinetic Energy KE of the CG KE about the CG = 1 2 mv G 2 + i = 1 n 1 2 m i v i / G 2 KE = i = 1 n 1 2 m i v i 2 m = i = 1 n m i Example: Two points on a rod Two components of KE
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2 Example: Two points on a rod KE of center of gravity KE about the center of gravity Multiparticle System Work terms are same as before: For example: PE = −∑ i = 1 n F c i ds i PE g = i = 1 n m i gh i W nc = i = 1 n F nc i ds i Example (prob. 5.3.1) Given: m 1
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This note was uploaded on 09/19/2009 for the course ME 242 taught by Professor Kam during the Spring '06 term at Nevada.

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ME 242 Lecture 22 03.27 - ME 242 Dynamics March 27, 2009...

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