ME 242 Lecture 27 04.08

# ME 242 Lecture 27 04.08 - ME 242 Dynamics April 8, 2009...

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1 ME 242 Dynamics April 8, 2009 Eric Wang Example (prob. 6.4.24) Given: ft and ft rad/s and rad/s Find: r C / O = 6 i r A / C = 2 j ω OC = 0.6 k AC / OC = 4.2 k a A No unknowns, just math! / C a A = a C + α OC × r A / C + OC × ( OC × r A / C ) a C = a O + OC × r C / O + OC × ( OC × r C / O ) = 2.16 i OC × ( OC × r A / C ) = 0.72 j + 2 OC × v rel + a rel Coriolis Acceleration + 2 OC × v A / C + a A / C a A = a C + OC × r A / C + OC × ( OC × r A / C ) v A / C = AC × r A / C 2 OC × v A / C = 10.08 j = 8.4 i Imagine you are standing at C. How fast is A moving? Finish it up + 2 OC × v A / C + a A / C a A = a C + OC × r A / C + OC × ( OC × r A / C ) a A / C = AC × AC × r A / C ( ) = 35.28 j = 2.16 i 46.08 j a A = 2.16 i 0.72 j 10.08 j 35.28 j Only centripetal acceleration Midterm Quiz #2 • This Friday • Chapters 3, 4, & 5 (skip 5.3 & 5.4) • Closed book, closed notes • Cheat sheet (1 page, 1 side) • Starts at noon (not 12:05

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2 Exam Questions • 2 “math” problems • Rest are multiple choice or T/F • Topics: – Single particles – Multi-particle systems – Force balance – Impulse-momentum – Impact
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## This note was uploaded on 09/19/2009 for the course ME 242 taught by Professor Kam during the Spring '06 term at Nevada.

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ME 242 Lecture 27 04.08 - ME 242 Dynamics April 8, 2009...

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