This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: No pages torn out of spiral notebooks Use only one side of the paper Double underline or box all answers (dont forget about the units) SOLUTION FIND GIVEN Page number Total number of pages in the assignment Course Due Date Assignment Number Last Name, First Name 1 / 6 Problem 3.16 GIVEN: The vehicle loaded as shown, where: G 1 = 4500 N 2 = 2500 N a = 0.6 m d=0.9m FIND: The reaction forces at the front and rear wheels, N f and N r SOLUTION FreeBody Diagram Assumptions : System is in static equilibrium. For equilibrium, F y =0 and M A =0 =0: N rG 1 +N f 2 = 0 =G +GN (0)G (1.5a)+N (2.5a)G (2.5a+d) = 0 =[G (1.5a)+G (2.5a+d)]/2.5a N r = G 1 +G 2[G = (G aG d)/2.5a Substituting values: N f ={(4500N)(1.5)(0.6m) + (2500N)[(2.5)(0.6m)+0.9m]} / (2.5)(0.6m) N f =6,700N N r = [(4500N)(0.6m)(2500N)(0.9m)] / (2.5)(0.6m) N r =300N ME241 Oct. 15, 2006 HW#6 Fine, Howard 1 / 2...
View
Full
Document
This note was uploaded on 09/19/2009 for the course ME 242 taught by Professor Kam during the Spring '06 term at Nevada.
 Spring '06
 KAM

Click to edit the document details