ME 242 Selected Answers Chapter 2

ME 242 Selected Answers Chapter 2 - (3 s) = (-1 . 20 * e t...

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2.2 Cartesian Coordinates 2.2.2 0 . 1 m/s 2.2.4 v 0 = - 100 m/s 2.2.6 s (4 s) - s (0) = 80 2 3 m 2.2.8 ¨ x (10) = 20 ft/s 2 2.2.10 t 2 = 7 s 2.2.14 h = 40 . 9 ft 2.2.16 y 2 = 13 . 45 km 2.2.18 v B = 30 . 2 ft/s = 20 . 6 mph 2.2.20 * p = - 8 . 70 * b 1 + 2 . 08 * b 2 2.2.22 * p = - 5 . 00 * b 1 - 0 . 01 * b 2 2.2.24 θ = 59 . 9 2.2.26 x max = 2 h 2.2.28 v 0 = 29 . 7 ft/s 2.2.30 a = 241 ft/s 2 , | v H | = 34 . 7 ft/s 2 2.2.32 v max = 10 . 09 m/s 2.2.34 t term = 0 . 00367 s 2.2.36 y (3) = - 3 v 0 3 xr 2 ± ± ( r 2 - x 2 ) 5 / 2 ± ± 2.2.38 v 0 = v u u t ² L + g ( - 3 π α ) 2 3 ³ 2 +4 d 2 4 ( - 3 π α ) 2 3 2.3 Polar/Cylindrical Coordi- nates 2.3.2 | ˙ r B / A | = . 949 v 2.3.4 Thus, the particle must be moving outward but not around the origin. 2.3.6 ˙ r = 10 sin(71 . 57 ) = 9 . 49 m / s 2.3.8 The speed of rotation is constant. 2.3.10 a r = a θ = 0 2.3.12 ˙ r = - 3 . 84 × 10 - 3 rad/s 2 2.3.14 | a B | = 0 . 106 m/s 2 2.3.16 ¨ r 6 = 193 . 6 ft/s 2 2.3.18 * v A = (2 . 207 * ) m/s * a A = (0 . 480 * ) m/s 2 2.3.20 ¨ θ = - 1 . 22 × 10 - 3 rad / s 2 2.3.22 ¨ L = 12 . 2 m / s 2 2.3.24 case 1: * a A = - 822 * e r m/s 2 , case 2: ¨ θ = - 2 . 74 × 10 5 rad/s 2 2.3.26 * a = - (6 . 42 * e r + 28 . 25 * e θ ) m/s 2 2.3.28 * a = - ra 2 ω 2 1 sin 2 ( ω 1 t ) * e r + raω 2 1 cos( ω 1 t ) * e θ + 2 2 cos( ω 2 t ) * k 2.3.30 k * a k = - 7 . 73 ft/s 2 2.3.32 % increase in speed = 0 . 016 % 2.4 Path Coordinates 2.4.2 a t = 5 m/s 2 2.4.4 r min = r C = 68 . 7 ft 2.4.6 * a P
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Unformatted text preview: (3 s) = (-1 . 20 * e t + 2 . 24 * e n ) ft/s 2 2.4.8 * v before = * v after = v b * i 2.4.10 r C = 899 ft 2.4.12 r C = 5115 km 2.4.14 s = 99 . 5 m 2.4.16 The car slips before exiting the turn. 2.5 Relative Motion and Con-straints 2.5.2 * v B = (30 * + 10 * ) m / s 2.5.4 * a S / B = 0 2.5.6 1 = 0 . 245 rad, 2 = 3 . 11 rad 2.5.8 = 159 2.5.10 * v box = 1 * m / s 2.5.12 * v A = 30 * in/s 2.5.14 * v D = 0 . 133 * m/s 2.5.16 * a A = 1 2 [ x 2 h 2 ( x 2 + h 2 )-1 . 5 + xx ( x 2 + h 2 )-. 5 ] * 2.5.18 * v B = v 8 * 2.5.20 * v B = 7 . 5 * m/s 2.5.22 * v B = 25 * in ./ s 2.5.24 * a B / A =-5 b * i + b (2- 2 ) * j 86...
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