Solution_1 - 1.15 Solution: Newton's II law "The...

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1.15 F grav = Force of gravity F app = Applied upward force m = mass of object a = net acceleration g = acceleration of gravity Solution: Newton’s II law “The relationship between an object's mass m , its acceleration a, and the applied force net F is F = ma .” F app - F grav = ma (1) F grav = mg (2) Substitute (2) to (1) F app = ma + mg (3) F app = (2 kg)(5 m/s 2 ) + (2 kg)(9.81m/s 2 ) (4) F app = 29.62 kg·m/s 2 (1N/1 kg·m/s 2 ) = 29.62 N (5)
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1.27 m = mass of gas p = gas pressure v = specific volume p 1 = initial pressure v 1 = specific volume of initial state p 2 = finial pressure V 2 = final volume Solution: The given pressure-specific volume relations: pv 1.3 = const p 1 v 1 1.3 = p 2 v 2 1.3 (1) (v 2 /v 1 ) 1.3 = (p 1 /p 2 ) (2) v 2 = v 1 (p 1 /p 2 ) 1/1.3 (3) = (0.2 m 3 /kg)(1/0.25) 1/1.3 =0.5810 m 3 /kg V 2 =mv 2 (4) = (5 kg)(0.5810 m 3 /kg) = 2.905 m 3 Pressure vs specific volume
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1.37 p A = pressure of tank A p B = pressure of tank B p Gage = gauge reading p atm = atmosphere pressure
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This note was uploaded on 09/20/2009 for the course ENGRD 2210 taught by Professor Torrance during the Fall '08 term at Cornell.

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Solution_1 - 1.15 Solution: Newton's II law "The...

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