01-02ChapGere.0017

# 01-02ChapGere.0017 - : d min 5 8 B 1200 kN 7 p (150 MPa) 5...

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48 CHAPTER 1 Tension, Compression, and Shear Solution 1.8-1 Aluminum tube in tension P 5 34k t 5 0.375in. s allow 5 9000psi P 5 s allow A 5 p t ( d 2 t ) s allow 5 p t ( d 2 t ) A 5 p 4 [ d 2 2 ( d 2 2 t ) 2 ] 5 p 4 (4 t )( d 2 t ) S OLVE FOR d: S UBSTITUTE NUMERICAL VALUES : d min 5 3.58 in. 5 3.207 in. 1 0.375 in. d min 5 34 k p (0.375 in.)(9000 psi) 1 0.375 in. d 5 P p t s allow 1 t P P d Problem 1.8-2 A steel pipe having yield stress s Y 5 270 MPa is to carry an axial compressive load P 5 1200 kN (see figure). A factor of safety of 1.8 against yielding is to be used. If the thickness t of the pipe is to be one-eighth of its outer diameter, what is the minimum required outer diameter d min ? P d t = d 8 Solution 1.8-2 Steel pipe in compression P 5 1200kN ± Y 5 270MPa n 5 1.8 s allow 5 150MPa S OLVE FOR d: S UBSTITUTE NUMERICAL VALUES
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Unformatted text preview: : d min 5 8 B 1200 kN 7 p (150 MPa) 5 153 mm d 2 5 64 P 7 p s allow Ê d 5 8 B P 7 p s allow d t = d 8 — P 5 s allow A 5 7 p d 2 64 s allow A 5 p 4 B d 2 2 ¢ d 2 d 4 ≤ 2 R 5 7 p d 2 64 Design for Axial Loads and Direct Shear Problem 1.8-1 An aluminum tube is required to transmit an axial tensile force P 5 34 k (see figure). The thickness of the wall of the tube is to be 0.375 in. What is the minimum required outer diameter d min if the allowable tensile stress is 9000 psi? P P d A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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