07-02ChapGere.0003

07-02ChapGere.0003 - s x 2 s y 5 2 0.6222 (b) M AXIMUM...

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Data for 7.3-12 s x 5 2100 kPa, s y 5 300 kPa, t xy 52 560 kPa Solution 7.3-12 Plane stress SECTION 7.3 Principal Stresses and Maximum Shear Stresses 441 (b) M AXIMUM SHEAR STRESSES and t 5 1690 psi and t 52 1690 psi s aver 5 s x 1 s y 2 5 2310 psi u s 2 5 u p 1 1 45 85 22.38 8 u s 1 5 u p 1 2 45 852 67.62 8 t max 5 B ¢ s x 2 s y 2 2 1 t xy 2 5 1690 psi } x O 1690 psi u s 2 5 22.38 8 2310 psi 2310 psi y s x 5 2100 kPa s y 5 300 kPa t xy 52 560 kPa (a) P RINCIPAL STRESSES 2 u p 5 2 31.89 8 and u p 5 2 15.95 8 2 u p 5 148.11 8 and u p 5 74.05 8 For 2 u p 5 2 31.89 8 : For 2 u p 5 148.11 8 : Therefore, s 1 5 2260 kPa and s 2 5 140 kPa and u p 2 5 74.05 8 u p 1 52 15.95 8 s x 1 5 140 kPa s x 1 5 2260 kPa s x 1 5 s x 1 s y 2 1 s x 2 s y 2 cos 2 u 1 t xy sin 2 u tan 2 u p 5 2 t xy
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Unformatted text preview: s x 2 s y 5 2 0.6222 (b) M AXIMUM SHEAR STRESSES and t 5 1060 kPa and t 5 2 1060 kPa s aver 5 s x 1 s y 2 5 1200 kPa u s 2 5 u p 1 1 45 8 5 29.05 8 u s 1 5 u p 1 2 45 8 5 2 60.95 8 t max 5 B ¢ s x 2 s y 2 ≤ 2 1 t xy 2 5 1060 kPa } } x O u p 2 5 74.05 8 2260 kPa 140 kPa y x O 1060 kPa u s 2 5 29.05 8 1200 kPa 1200 kPa y A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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