01-02ChapGere.0012 - M AXIMUM CLAMPING FORCE C ult t ult 5...

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SECTION 1.7 Allowable Loads 43 Problem 1.7-10 Ametal bar AB of weight W is suspended by a system of steel wires arranged as shown in the figure. The diameter of the wires is 2 mm, and the yield stress of the steel is 450 MPa. Determine the maximum permissible weight W max for a factor of safety of 1.9 with respect to yielding. 1.75 m A W B 1.75 m 0.75 m 0.75 m 2.5 m Solution 1.7-9 Forces in pliers F REE - BODY DIAGRAM OF ONE ARM C 5 clamping force R 5 reaction at pin a 5 3.75in. b 5 1.60in. d 5 diameter of pin 5 0.20in. S F vert 5 0 1 2 P 1 C 2 R 5 0 R 5 P 1 C 5 P ¢ 1 1 a b 5 C ¢ 1 1 b a C 5 Pa b Ê P 5 Cb a Ê C P 5 a b © M pin 5 0 Ê `~ Ê Cb 2 Pa 5 0 b a P Pin R C V 5 shear force in pin (single shear)
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Unformatted text preview: M AXIMUM CLAMPING FORCE C ult t ult 5 50ksi V ult 5 t ult A pin 5 1571lb 5 1100lb M AXIMUM LOAD P ult A LLOWABLE LOAD P allow 5 157 lb P allow 5 P ult n 5 469.8 lb 3.0 P ult 5 V ult 1 1 a b 5 1571 lb 1 1 3.75 in. 1.60 in. 5 469.8 lb C ult 5 V ult 1 1 b a 5 1571 lb 1 1 1.60 in. 3.75 in. 5 (50 ksi) p 4 (0.20 in.) 2 V 5 R C 5 V 1 1 b a and P 5 V 1 1 a b A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

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