01-02ChapGere.0030

# 01-02ChapGere.0030 - 5 (sin u cos u )(2)(cos u )( 2 sin u )...

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SECTION 1.8 Design for Axial Loads and Direct Shear 61 A NGLE u THAT MAKES W A MINIMUM Use Eq. (2) Let S ET THE NUMERATOR 5 0 AND SOLVE FOR u : 2 sin 2 u cos 2 u 1 sin 2 u 2 cos 2 u 2 cos 4 u 5 0 Replace sin 2 u by 1 2 cos 2 u : 2 (1 2 cos 2 u )(cos 2 u ) 1 1 2 cos 2 u 2 cos 2 u 2 cos 4 u 5 0 Combine terms to simplify the equation: u 5 54.7 8 1 2 3 cos 2 u 5 0 Ê cos u 5 1 Ï 3 5 2 sin 2 u cos 2 u 1 sin 2 u 2 cos 2 u 2 cos 4 u sin 2 u cos 2 u df d u
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Unformatted text preview: 5 (sin u cos u )(2)(cos u )( 2 sin u ) 2 (1 1 cos 2 u )( 2 sin 2 u 1 cos 2 u ) sin 2 u cos 2 u df d u 5 f 5 1 1 cos 2 u sin u cos u A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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