02-01ChapGere.0008

02-01ChapGere.0008 - x 5 0.1347 m x 5 135 mm L 1 1 d 1 5 h...

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Solution 2.2-10 Bar supported by two springs 70 CHAPTER 2 Axially Loaded Members P x A d 1 k 1 k 2 L 2 B W d 2 L 1 h L 2 L 2 Reference line W 5 25 N k 1 5 300 N/m k 2 5 400 N/m L 5 350 mm h 5 80 mm P 5 18 N N ATURAL LENGTHS OF SPRINGS L 1 5 250 mm L 2 5 200 mm O BJECTIVE Find distance x for bar AB to be horizontal. F REE - BODY DIAGRAM OF BAR AB (Eq. 1) c 1 T 2 F 1 1 F 2 2 P 2 W 5 0 (Eq. 2) S OLVE E QS . (1) AND (2): S UBSTITUTE NUMERICAL VALUES : U NITS : Newtons and meters E LONGATIONS OF THE SPRINGS B AR AB REMAINS HORIZONTAL Points A and B are the same distance below the reference line (see figure above). or 0.250 1 0.10167 2 0.17143 x 5 0.080 1 0.200 1 0.12857 x 1 0.031250 S OLVE FOR x : 0.300 x 5 0.040420
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Unformatted text preview: x 5 0.1347 m x 5 135 mm L 1 1 d 1 5 h 1 L 2 1 d 2 d 2 5 F 2 k 2 5 F 2 400 5 0.12857 x 1 0.031250 d 1 5 F 1 k 1 5 F 1 300 5 0.10167 2 0.17143 x F 2 5 (18) x 0.350 1 12.5 5 51.429 x 1 12.5 F 1 5 (18) 1 2 x 0.350 1 12.5 5 30.5 2 51.429 x F 1 5 P 1 2 x L 1 W 2 F 2 5 P x L 1 W 2 F vert 5 F 2 L 2 P X 2 WL 2 5 M A 5 ` ~ P x A B W F 1 F 2 L 2 L 2 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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