02-01ChapGere.0012

02-01ChapGere.0012 - b 5 200 mm, k 5 3.2 kN/m, a 5 45, and...

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74 CHAPTER 2 Axially Loaded Members D ETERMINE THE ANGLE u D S 5 elongation of spring 5 S 2 2 S 1 5 b (cos u 2 cos a ) For the spring: F 5 k ( D S ) F 5 bk (cos u 2 cos a ) Substitute F into Eq. (1): P cos u 5 bk (cos u 2 cos a )(sin u ) (Eq. 2) This equation must be solved numerically for the angle u . D ETERMINE THE DISTANCE d d 5 L 2 2 L 1 5 2 b cos u 2 2 b cos a 5 2 b (cos u 2 cos a ) or Ê P bk cot u 2 cos u 1 cos a 5 0 From Eq. (2): Therefore, (Eq. 3) N UMERICAL RESULTS b 5 8.0 in. k 5 16 lb/in. a 5 45 8 P 5 10 lb Substitute into Eq. (2): 0.078125 cot u 2 cos u 1 0.707107 5 0 (Eq. 4) Solve Eq. (4) numerically: Substitute into Eq. (3): d 5 1.78 in. u 5 35.1 8 5 2 P b cot u Ê d 5 2 b ¢ cos u 2 cos u 1 P cot u bk cos a 5 cos u 2 P cot u bk Problem 2.2-14 Solve the preceding problem for the following data:
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Unformatted text preview: b 5 200 mm, k 5 3.2 kN/m, a 5 45, and P 5 50 N. Solution 2.2-14 Framework with rigid bars and a spring See the solution to the preceding problem. Eq. (2): Eq. (3): d 5 2 P k cot u P bk cot u 2 cos u 1 cos a 5 N UMERICAL RESULTS b 5 200 mm k 5 3.2 kN/m a 5 45 8 P 5 50 N Substitute into Eq. (2): 0.078125 cot u 2 cos u 1 0.707107 5 (Eq. 4) Solve Eq. (4) numerically: Substitute into Eq. (3): d 5 44.5 mm u 5 35.1 8 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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