SECTION 2.5Misfits and Prestrains115Solution 2.5-13Bar with a gapL25 in.S0.008 in.T50 F (increase)9.6 106/ FE16 106psielongation of the bar if it is free to expand(T)LCelongation that is prevented by the support(T)LSeCstrain in the bar due to the restraintC/Lcstress in the barNote: This result is valid only if (T)LS.(Otherwise, the gap is not closed).Substitute numerical values:0.008 in.]2,560psi[ (9.6106F)(50 F)(25in.)sc16106psi25in.EeCECLEL[(¢T)LS]LABSProblem 2.5-14A bar ABhaving length Land axial rigidity EAis fixedat end A(see figure). At the other end a small gap of dimension sexistsbetween the end of the bar and a rigid surface. A load Pacts on the bar atpoint C, which is two-thirds of the length from the fixed end. If the support reactions produced by the load Pare to be equal inmagnitude, what should be the size sof the gap?Solution 2.5-14Bar with a gap (load P)BACP2L3—L3—sLlength of barSsize of gap
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