02-03ChapGere.0015 - 120 A-PDF Axially Loaded : Purchase...

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120 CHAPTER 2 Axially Loaded Members Problem 2.5-19 Solve the preceding problem if the data for the assembly are as follows: length L 5 10 in., pitch of the bolt threads p 5 0.058 in., modulus of elasticity for steel E s 5 30 3 10 6 psi, modulus of elasticity for the plastic E p 5 500 ksi, cross-sectional area of one bolt A s 5 0.06 in. 2 , and cross-sectional area of the plastic cylinder A p 5 1.5 in. 2 Solution 2.5-19 Plastic cylinder and two steel bolts L 5 10 in. p 5 0.058 in. E s 5 30 3 10 6 psi A s 5 0.06 in. 2 (for one bolt) E p 5 500 ksi A p 5 1.5 in. 2 n 5 1 (see Eq. 2-22) E QUILIBRIUM EQUATION P s 5 tensile force in one steel bolt P p 5 compressive force in plastic cylinder P p 5 2 P s (Eq. 1) C OMPATIBILITY EQUATION d s 5 elongation of steel bolt d p 5 shortening of plastic cylinder d s 1 d p 5 np (Eq. 2) F ORCE - DISPLACEMENT RELATIONS
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

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