02-04ChapGere.0011

# 02-04ChapGere.0011 - 132 A-PDF Axially Loaded Purchase...

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Unformatted text preview: 132 A-PDF Axially Loaded : Purchase CHAPTER 2 Split DEMOMembers Solution 2.6-14 y P x P from www.A-PDF.com to remove the watermark Two boards joined by a scarf joint 10 40 x 33.34 4.9 MPa 20 90 Since or < 56.66 56.66 or 33.34 Due to load P: (a) STRESSES ON JOINT WHEN n = 90 a must be between 10 and 40 , we select 33.3 Note: If | | If 90 x is between 10 and 33.3 , 2.25 MPa. is between 33.3 and 40 , 2.25 MPa. WHAT IS 70 cos2 (4.9 MPa)(cos 70 )2 | | (c) if 2 ? 0.57 MPa x Numerical values only: cos ` | | tu ` su x x sin sin cos | | x cos2 ( 4.9 MPa)(sin 70 )(cos 70 ) 1.58 MPa (b) LARGEST ANGLE allow x sin 2 cos 2 cos 63.43 2 xcos2 or tan 90 2 sin IF allow 2.25 MPa sin cos a The shear stress on the joint has a negative sign. Its numerical value cannot exceed allow 2.25 MPa. Therefore, 2.25 MPa sin cos (4.9 MPa)(sin )(cos ) or 0.4592 1 sin 2u 2 0.9184 26.6 NOTE: For 26.6 and 63.4 , we find 0.98 MPa and 1.96 MPa. Thus, ` tu ` su From trigonometry: sin u cos u Therefore: sin 2 Solving : 2 2(0.4592) or 2 as required. 66.69 113.31 ...
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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