02-05ChapGere.0007

02-05ChapGere.0007 - E u 5 U V 5 s 2 2 E Stress s 5 P A U 5...

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Problem 2.7-5 Determine the strain energy per unit volume (units of psi) and the strain energy per unit weight (units of in.) that can be stored in each of the materials listed in the accompanying table, assuming that the material is stressed to the proportional limit. DATA FOR PROBLEM 2.7-5 Weight Modulus of Proportional density elasticity limit Material (lb/in. 3 ) (ksi) (psi) Mild steel 0.284 30,000 36,000 Tool steel 0.284 30,000 75,000 Aluminum 0.0984 10,500 60,000 Rubber (soft) 0.0405 0.300 300 Solution 2.7-5 Strain-energy density D ATA : 140 CHAPTER 2 Axially Loaded Members S TRAIN ENERGY PER UNIT VOLUME Volume V 5 AL At the proportional limit: u 5 u R 5 modulus of resistance (Eq. 1) u R 5 s PL 2 2
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Unformatted text preview: E u 5 U V 5 s 2 2 E Stress s 5 P A U 5 P 2 L 2 EA S TRAIN ENERGY PER UNIT WEIGHT Weight W 5 g AL g 5 weight density At the proportional limit: (Eq. 2) R ESULTS u W 5 s PL 2 2 g E u W 5 U W 5 s 2 2 g E U 5 P 2 L 2 EA Weight Modulus of Proportional density elasticity limit Material (lb/in. 3 ) (ksi) (psi) Mild steel 0.284 30,000 36,000 Tool steel 0.284 30,000 75,000 Aluminum 0.0984 10,500 60,000 Rubber (soft) 0.0405 0.300 300 u R u W (psi) (in.) Mild steel 22 76 Tool steel 94 330 Aluminum 171 1740 Rubber (soft) 150 3700 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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