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02-06ChapGere.0007

# 02-06ChapGere.0007 - A 5 0.25 in 2 and the modulus of...

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Problem 2.8-2 Solve the preceding problem if the collar has mass M 80 kg, the height h 0.5 m, the length L 3.0 m, the cross-sectional area A 350 mm 2 , and the modulus of elasticity E 170 GPa. Solution 2.8-2 Collar falling onto a flange 150 CHAPTER 2 Axially Loaded Members M 80 kg W Mg (80 kg)(9.81 m/s 2 ) 784.8 N h 0.5 m L 3.0 m E 170 GPa A 350 mm 2 (a) D OWNWARD DISPLACEMENT OF FLANGE (b) M AXIMUM TENSILE STRESS (E Q . 2-55) (c) I MPACT FACTOR (E Q . 2-61) 160 Impact factor max st 6.33 mm 0.03957 mm s max E max L 359 MPa 6.33 mm Eq. (2-53): max st B 1 ¢ 1 2 h st 1 2 R st WL EA 0.03957 mm Flange L h W Problem 2.8-3 Solve Problem 2.8-1 if the collar has weight W 50 lb, the height h 2.0 in., the length
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Unformatted text preview: A 5 0.25 in. 2 , and the modulus of elasticity E 5 30,000 ksi. Solution 2.8-3 Collar falling onto a flange Flange L h W W 5 50lb h 5 2.0in. L 5 3.0ft 5 36in. E 5 30,000psi A 5 0.25in. 2 (a) D OWNWARD DISPLACEMENT OF FLANGE (b) M AXIMUM TENSILE STRESS (E Q . 2-55) (c) I MPACT FACTOR (E Q . 2-61) 5 130 Impact factor 5 d max d st 5 0.0312 in. 0.00024 in. s max 5 E d max L 5 26,000 psi 5 0.0312 in. Eq. (2-53): Ê d max 5 d st B 1 1 ¢ 1 1 2 h d st ≤ 1 / 2 R d st 5 WL EA 5 0.00024 in. A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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