02-06ChapGere.0011

02-06ChapGere.0011 - Slider h L W 5 Mg 5 (35kg)(9.81m/s 2 )...

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Problem 2.8-9 Solve the preceding problem if the slider has weight W 5 100 lb, h 5 45 in., A 5 0.080 in. 2 , E 5 21 3 10 6 psi, and the allowable stress is 70 ksi. Problem 2.8-8 A cable with a restrainer at the bottom hangs vertically from its upper end (see figure). The cable has an effective cross-sectional area A 5 40 mm 2 and an effective modulus of elasticity E 5 130 GPa. A slider of mass M 5 35 kg drops from a height h 5 1.0 m onto the restrainer. If the allowable stress in the cable under an impact load is 500 MPa, what is the minimum permissible length L of the cable? Solution 2.8-8 Slider on a cable 154 CHAPTER 2 Axially Loaded Members Restrainer Cable
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Unformatted text preview: Slider h L W 5 Mg 5 (35kg)(9.81m/s 2 ) 5 343.4N A 5 40mm 2 E 5 130GPa h 5 1.0m s allow 5 s max 5 500MPa Find minimum length L min S TATIC STRESS M INIMUM LENGTH L min or Square both sides and solve for L : S UBSTITUTE NUMERICAL VALUES : 5 9.25 mm L min 5 2(130 GPa)(1.0 m)(8.585 MPa) (500 MPa)[500 MPa 2 2(8.585 MPa)] L 5 L min 5 2 Eh s st s max ( s max 2 2 s st ) s max s st 2 1 5 1 1 2 hE L s st 1 / 2 Eq. (2-59): s max 5 s st B 1 1 1 1 2 hE L s st 1 / 2 R s st 5 W A 5 343.4 N 40 mm 2 5 8.585 MPa h L W Probs. 2.8-8 and 2.8-9 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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