Problem 2.11-6A rigid bar AB, pinned at end A, is supported by a wireCDand loaded by a force Pat end B(see figure). The wire is made ofhigh-strength steel having modulus of elasticity E 5 210 GPa and yieldstress sY 5 820 MPa. The length of the wire is L5 1.0 m and itsdiameter is d 5 3 mm. The stress-strain diagram for the steel is definedby the modified power law, as follows:s5 Ee0 # s# sYs5 sY1}EseY}2ns$sY(a) Assuming n 5 0.2, calculate the displacement dBat the end of thebar due to the load P. Take values of Pfrom 2.4 kN to 5.6 kN inincrements of 0.8 kN. (b) Plot a load-displacement diagram showing Pversus dB.Solution 2.11-6Rigid bar supported by a wire170CHAPTER 2Axially Loaded MembersPADCBLb2bWire: E5210GPasY5820MPaL51.0md53mmSTRESS-STRAIN DIAGRAM(1)(2)(a) DISPLACEMENTdBAT END OF BAR(3)Obtain efrom stress-strain equations:(4)FromEq.(1):Êe5sEÊ(0#s#sY)d5elongationofwireÊdB532d532e
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