03-01ChapGere.0002

03-01ChapGere.0002 - 5 400 3 10 2 6 rad 218.2 3 10 2 6 rad...

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Problem 3.2-3 A circular aluminum tube subjected to pure torsion by torques T (see figure) has an outer radius r 2 equal to twice the inner radius r 1 . (a) If the maximum shear strain in the tube is measured as 400 3 10 2 6 rad, what is the shear strain g 1 at the inner surface? (b) If the maximum allowable rate of twist is 0.15 degrees per foot and the maximum shear strain is to be kept at 400 3 10 2 6 rad by adjusting the torque T , what is the minimum required outer radius ( r 2 ) min ? Solution 3.2-3 Circular aluminum tube 182 CHAPTER 3 Torsion L T r 1 r 2 T r 2 5 2 r 1 g max 5 400 3 10 2 6 rad (a) S HEAR STRAIN AT INNER SURFACE From Eq. (3-5b): g 1 5 200 3 10 2 6 rad g 1 5 1 2 g 2 5 1 2 (400 3 10 2 6 rad) 5 218.2 3 10 2 6 rad / in. 5 (0.15 8 / ft) ¢ p 180 rad degree ≤¢ 1 12 ft in. u allow 5 0.15 8 / ft (b) M INIMUM OUTER RADIUS From Eq. (3-5a): ( r 2 ) min 5 1.83 in. ( r 2 ) min 5 g max u allow
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Unformatted text preview: 5 400 3 10 2 6 rad 218.2 3 10 2 6 rad / in. g max 5 r 2 f L 5 r 2 u r 1 r 2 Problem 3.2-4 A circular steel tube of length L 5 0.90 m is loaded in torsion by torques T (see figure). (a) If the inner radius of the tube is r 1 5 40 mm and the measured angle of twist between the ends is 0.5, what is the shear strain g 1 (in radians) at the inner surface? (b) If the maximum allowable shear strain is 0.0005 rad and the angle of twist is to be kept at 0.5 by adjusting the torque T , what is the maximum permissible outer radius ( r 2 ) max ? Problems 3.2-3, 3.2-4, and 3.2-5 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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