03-01ChapGere.0003

# 03-01ChapGere.0003 - 1.5 in(a S HEAR STRAIN AT INNER...

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SECTION 3.2 Torsional Deformations 183 Solution 3.2-4 Circular steel tube L 5 0.90 m r 1 5 40 mm (a) S HEAR STRAIN AT INNER SURFACE From Eq. (3-5b): g 1 5 388 3 10 2 6 rad g min 5 g 1 5 r 1 f L 5 (40 mm)(0.008727 rad) 900 mm g max 5 0.0005 rad 5 0.008727 rad f 5 0.5 85 (0.5 8 ) ¢ p 180 rad degree (b) M AXIMUM OUTER RADIUS From Eq. (3-5a): ( r 2 ) max 5 51.6 mm ( r 2 ) max 5 (0.0005 rad)(900 mm) 0.008727 rad r 2 5 g max L f g max 5 g 2 5 r 2 f L ; r 1 r 2 Problem 3.2-5 Solve the preceding problem if the length L 5 50 in., the inner radius r 1 5 1.5 in., the angle of twist is 0.6°, and the allowable shear strain is 0.0004 rad. Solution 3.2-5 Circular steel tube L 5 50 in. r 1 5
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Unformatted text preview: 1.5 in. (a) S HEAR STRAIN AT INNER SURFACE From Eq. (3-5b): g 1 5 314 3 10 2 6 rad g min 5 g 1 5 r 1 f L 5 (1.5 in.)(0.010472 rad) 50 in. g max 5 0.0004 rad 5 0.010472 rad f 5 0.6 8 5 (0.6 8 ) ¢ p 180 rad degree ≤ (b) M AXIMUM OUTER RADIUS From Eq. (3-5a): ( r 2 ) max 5 1.91 in. ( r 2 ) max 5 (0.0004 rad)(50 in.) 0.010472 rad g max 5 g 2 5 r 2 f L ; r 2 5 g max L f r 1 r 2 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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