03-01ChapGere.0007

# 03-01ChapGere.0007 - Socket wrench L = 200 mm d = 8.0 mm T...

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Solution 3.3-5 Steel drill rod SECTION 3.3 Circular Bars and Tubes 187 G 5 11,600 psi d 5 0.5 in. t allow 5 40 ksi M INIMUM LENGTH From Eq. (3-12): (1) t max 5 16 T p d 3 f 5 30 85 (30 8 ) ¢ p 180 rad 5 0.52360 rad From Eq. (3-15): ; substitute T into Eq. (1): L min 5 38.0 in. 5 (11,600 ksi)(0.5 in.)(0.52360 rad) 2(40 ksi) L min 5 Gd f 2 t allow t max 5 ¢ 16 p d 3 ≤¢ G p d 4 f 32 L 5 Gd f 2 L T 5 G p d 4 f 32 L f 5 TL GI P 5 32 TL G p d 4 d T T L Problem 3.3-6 The steel shaft of a socket wrench has a diameter of 8.0 mm. and a length of 200 mm (see figure). If the allowable stress in shear is 60 MPa, what is the maximum permissible torque T max that may be exerted with the wrench? Through what angle f (in degrees) will the shaft twist under the action of the maximum torque? (Assume G 5 78 GPa and disregard any bending of the shaft.) Solution 3.3-6
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Unformatted text preview: Socket wrench L = 200 mm d = 8.0 mm T d 5 8.0 mm L 5 200 mm t allow 5 60 MPa G 5 78 GPa M AXIMUM PERMISSIBLE TORQUE From Eq. (3-12): T max 5 6.03 N # m T max 5 p (8.0 mm) 3 (60 MPa) 16 T max 5 p d 3 t max 16 t max 5 16 T p d 3 A NGLE OF TWIST From Eq. (3-15): From Eq. (3-12): f 5 (0.03846 rad) ¢ 180 p deg / rad ≤ 5 2.20 8 f 5 2(60 MPa)(200 mm) (78 GPa)(8.0 mm) 5 0.03846 rad f 5 p d 3 t max L (32) 16 G ( p d 4 ) 5 2 t max L Gd f 5 ¢ p d 3 t max 16 ≤ ¢ L GI P ≤ Ê I P 5 p d 4 32 T max 5 p d 3 t max 16 f 5 T max L GI P L d T A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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