Problem 3.3-7A circular tube of aluminum is subjected totorsion by torques Tapplied at the ends (see figure). The bar is20 in. long, and the inside and outside diameters are 1.2 in. and1.6 in., respectively. It is determined by measurement that theangle of twist is 3.63° when the torque is 5800 lb-in. Calculate the maximum shear stress tmaxin the tube, theshear modulus of elasticity G, and the maximum shear straingmax(in radians).Solution 3.3-7Aluminum tube in torsion188CHAPTER 3Torsion1.6 in.1.2 in.20 in.TTL520 in.d151.2 in.d251.6 in.T55800 lb-in.f53.63850.063355 radMAXIMUM SHEAR STRESStmax510,550psitmax5TrIP5(5800lb-in.)(0.8in.)0.43982in.4IP5p32(d242d14)50.43982in.4SHEAR MODULUS OF ELASTICITYMAXIMUM SHEAR STRAIN
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Shear modulus, maximum shear stress, maximum shear strain, gmax gmax gmax