03-01ChapGere.0009

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Solution 3.3-8 Propeller shaft SECTION 3.3 Circular Bars and Tubes 189 d 5 100 mm G 5 80 GPa t allow 5 50 MPa M AX . TORQUE BASED UPON SHEAR STRESS T 1 5 9820 N ? m 5 p (100 mm) 3 (50 MPa) 16 t 5 16 T p d 3 Ê T 1 5 p d 3 t allow 16 5 0.011636 rad / m u 5 2 8 in 3 m 5 1 3 (2 8 ) ¢ p 180 rad / m M AX . TORQUE BASED UPON RATE OF TWIST R ATEOF TWIST GOVERNS T max 5 9140 N ? m T 2 5 9140 N ? m 5 (80 GPa) ¢ p 32 (100 mm) 4 (0.011636 rad / m) u 5 T GI P Ê T 2 5 GI P u 5 G ¢ p d 4 32 u T T d Problem 3.3-9 Three identical circular disks A , B , and C are welded to the ends of three identical solid circular bars (see figure). The bars lie in a common plane and the disks lie in planes perpendicular to the axes of the bars. The bars are welded at their intersection
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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