Solution 3.3-8Propeller shaftSECTION 3.3Circular Bars and Tubes189d5100 mmG580 GPatallow550 MPaMAX. TORQUE BASED UPON SHEAR STRESST159820N ?m5p(100mm)3(50MPa)16t516Tpd3ÊT15pd3tallow1650.011636rad/mu528in3m513(28)¢p180≤rad/mMAX. TORQUE BASED UPON RATE OF TWISTRATEOF TWIST GOVERNSTmax59140N?mT259140N?m5(80GPa)¢p32≤(100mm)4(0.011636rad/m)u5TGIPÊT25GIPu5G¢pd432≤uTTdProblem 3.3-9Three identical circular disks A, B, and Care welded tothe ends of three identical solid circular bars (see figure). The bars lie in a common plane and the disks lie in planes perpendicular to the axes of the bars. The bars are welded at their intersection
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.