03-02ChapGere.0026 - of the bar is d 2 5 3.0 in. and the...

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SECTION 3.8 Statically Indeterminate Torsional Members 229 Solution 3.8-8 Fixed-end bar with triangular load A t ( x ) t 0 T B T A B L x dx T 0 5 Resultant of distributed torque E QUILIBRIUM T A 1 T B 5 T 0 5 t 0 L 2 T 0 5 # L 0 t ( x ) dx 5 # L 0 t 0 x L dx 5 t 0 L 2 t ( x ) 5 t 0 x L E LEMENT OF DISTRIBUTED LOAD dT A 5 Elemental reactive torque dT B 5 Elemental reactive torque From Eqs. (3-46a and b): R EACTIVE TORQUES ( FIXED - END TORQUES ) N OTE : T A 1 T B 5 t 0 L 2 T B 5 # dT B 5 # L 0 ¢ t 0 x L ¢ x L dx 5 t 0 L 3 T A 5 # dT A 5 # L 0 ¢ t 0 x L ¢ L 2 x L dx 5 t 0 L 6 dT A 5 t ( x ) dx ¢ L 2 x L Ê dT B 5 t ( x ) dx ¢ x L t ( x )dx dT B dT A B x dx Problem 3.8-9 A circular bar AB with ends fixed against rotation has a hole extending for half of its length (see figure). The outer diameter
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Unformatted text preview: of the bar is d 2 5 3.0 in. and the diameter of the hole is d 1 5 2.4 in. The total length of the bar is L 5 50 in. At what distance x from the left-hand end of the bar should a torque T be applied so that the reactive torques at the supports will be equal? B A x 3.0 in. T 2.4 in. 3.0 in. 25 in. 25 in. A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

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