04-01ChapGere.0005 - P 2 ¢ H 2 1 b tan b ≤ M 5 T ¢ H 2...

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Solution 4.3-8 Archer’s bow SECTION 4.3 Shear Forces and Bending Moments 263 P 5 130 N b 5 70° H 5 1400 mm 5 1.4 m b 5 350 mm 5 0.35 m Free-body diagram of point A T 5 tensile force in the bowstring S F HORIZ 5 0: 2 T cos b 2 P 5 0 T 5 P 2 cos b Free-body diagram of segment BC Substitute numerical values : M 5 108 N ? m M 5 130 N 2 B 1.4 m 2 1 (0.35 m)(tan 70 8 ) R 5
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Unformatted text preview: P 2 ¢ H 2 1 b tan b ≤ M 5 T ¢ H 2 cos b 1 b sin b ≤ T (cos b ) ¢ H 2 ≤ 1 T (sin b ) ( b ) 2 M 5 © M C 5 ` ~ b H P A b C B P A T b T H 2 C b B T b M A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

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