04-01ChapGere.0007

# e 265 p cable a b c d 8 ft 6 ft 6 ft 6 ft solution

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Unformatted text preview: ) E 265 P Cable A B C D 8 ft 6 ft 6 ft 6 ft Solution 4.3-11 Beam with a cable E P Free-body diagram of section AC P Cable P A 6 ft 4P __ 9 B 6 ft C 6 ft D 8 ft P 4P __ 9 4P __ 9 A 6 ft 4P __ 5 B 3P __ 5 6 ft C M N V MC M 0 UNITS: P in lb M in lb-ft 4P 4P (6 ft) (12 ft) 0 5 9 8P M lb-ft 15 Numerical value of M equals 640 lb-ft. 8P lb-ft 15 1200 lb 640 lb-ft and P Problem 4.3-12 A simply supported beam AB supports a trapezoidally distributed load (see figure). The intensity of the load varies linearly from 50 kN/m at support A to 30 kN/m at support B. Calculate the shear force V and bending moment M at the midpoint of the beam. 50 kN/m 30 kN/m A B 3m...
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Tech.

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