SECTION 4.5Shear-Force and Bending-Moment Diagrams281BA3.0 kN/m1.0 kN/m2.4 mRA = 2.0 kNRB = 2.8 kNSet V50:x151.2980 mV52.02x2x22.4Ê(x5meters; V5kN)M(kN .m)22.82.000Mmax= 1.450x1= 1.2980 mxV(kN)Problem 4.5-25A beam of length Lis being designed to support a uniform loadof intensity q(see figure). If the supports of the beam are placed at the ends,creating a simple beam, the maximum bending moment in the beam is qL2/8.However, if the supports of the beam are moved symmetrically toward the middleof the beam (as pictured), the maximum bending moment is reduced. Determine the distance abetween the supports so that the maximum bendingmoment in the beam has the smallest possible numerical value. Draw the shear-force and bending-moment diagrams for this
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Second moment of area, maximum bending moment, qL/2