05-01ChapGere.0016 - M AXIMUM STRESSES s t 5 6,560 psi s c...

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Problem 5.5-19 A beam ABC with an overhang from B to C supports a uniform load of 160 lb/ft throughout its length (see figure). The beam is a channel section with dimensions as shown in the figure. The moment of inertia about the z axis (the neutral axis) equals 5.14 in. 4 Calculate the maximum tensile stress t and maximum compressive stress c due to the uniform load. Solution 5.5-19 Beam with an overhang 300 CHAPTER 5 Stresses in Beams (Basic Topics) A B C 10 ft 5 ft 160 lb/ft z y C 0.674 in. 2.496 in. L 10 ft q 160 lb/ft C B A b 5 ft z y C 0.674 in. 2.496 in. 0 M 1 M 2 3.75 ft I z 5.14 in. 4 c 1 0.674 in. c 2 2.496 in. R A 600 lb R B 1800 lb M 1 1125 lb-ft 13,500 lb-in. M 2 2000 lb-ft 24,000 lb-in. A T CROSS SECTION OF MAXIMUM POSITIVE BENDING MOMENT A T CROSS SECTION OF MAXIMUM NEGATIVE
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Unformatted text preview: M AXIMUM STRESSES s t 5 6,560 psi s c 5 11,650 psi s c 5 M 2 c 2 I z 5 (24,000 lb-in.)(2.496 in.) 5.14 in. 4 5 11,650 psi s t 5 M 2 c 1 I z 5 (24,000 lb-in.)(0.674 in.) 5.14 in. 4 5 3,150 psi s c 5 M 1 c 1 I z 5 (13,500 lb-in.)(0.674 in.) 5.14 in. 4 5 1,770 psi s t 5 M 1 c 2 I z 5 (13,500 lb-in.)(2.496 in.) 5.14 in. 4 5 6,560 psi Problem 5.5-20 A frame ABC travels horizontally with an acceleration a (see figure). Obtain a formula for the maximum stress s max in the vertical arm AB , which has length L , thickness t , and mass density r . L C B A t a = acceleration A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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