05-03ChapGere.0009 - : P max 5 (3.5 in.) (7.0 in.) 5 6500...

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Problem 5.8-3 Two wood beams, each of square cross section (3.5 in. 3 3.5 in., actual dimensions) are glued together to form a solid beam of dimensions 3.5 in. 3 7.0 in. (see figure). The beam is simply supported with a span of 6 ft. What is the maximum load P max that may act at the midpoint if the allowable shear stress in the glued joint is 200 psi? (Include the effects of the beam’s own weight, assuming that the wood weighs 35 lb/ft 3 .) Solution 5.8-3 Simple beam with a glued joint SECTION 5.8 Shear Stresses in Rectangular Beams 329 7.0 in. 3.5 in. P 6 ft L /2 L /2 P h /2 h /2 b q L 5 6 ft 5 72 in. b 5 3.5 in. h 5 7.0 in. q 5 weight of beam per unit distance 5 g bh M AXIMUM LOAD P max 5 bh ¢ 4 3 t 2 g L P max 5 4 3 bh t 2 qL 5 4 3 bh t 2 g bhL t max 5 3 V 2 A 5 3 ¢ P 2 1 qL 2 2 bh 5 3 4 bh ( P 1 qL ) V 5 P 2 1 qL 2 Ê A 5 bh g 5 (35 lb / ft 3 ) ¢ 1 1728 ft 3 in. 3 5 35 1728 lb / in. 3 t allow 5 200 psi S UBSTITUTE NUMERICAL VALUES
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Unformatted text preview: : P max 5 (3.5 in.) (7.0 in.) 5 6500 lb (This result is based solely on the shear stress.) 3 B 4 3 (200 psi) 2 35 1728 lb / in. 3 (72 in.) R Problem 5.8-4 A cantilever beam of length L 5 2 m supports a load P 5 8.0 kN (see figure). The beam is made of wood with cross-sectional dimensions 120 mm 3 200 mm. Calculate the shear stresses due to the load P at points located 25 mm, 50 mm, 75 mm, and 100 mm from the top surface of the beam. From these results, plot a graph showing the distribution of shear stresses from top to bottom of the beam. 200 mm 120 mm L = 2 m P = 8.0 kN A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

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