05-04ChapGere.0004 - 14 MPa t 5 4 V 3 ¢ 61 41 ≤ ¢ 100 9...

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Solution 5.9-4 Wind load on a sign SECTION 5.9 Shear Stresses in Circular Beams 341 d h 2 = 1.5 m h 1 = 6.0 m W b 5 width of sign b 5 3.0 m p 5 3.6 kPa s allow 5 50 MPa t allow 5 16 MPa d 5 diameter W 5 wind force on one pole (a) R EQUIRED DIAMETER BASED UPON BENDING STRESS ( d 5 meters) 5 0.018866 m 3 d 5 0.266 m 5 266 mm d 3 5 17.253 M max s allow 5 (17.253)(54.675 kN ? m) 50 MPa s 5 Mc I 5 M ( d / 2) 369 p d 4 / 40,000 5 17.253 M d 3 c 5 d 2 I 5 p 64 B d 4 2 ¢ 4 d 5 4 R 5 p d 4 64 ¢ 369 625 5 369 p d 4 40,000 (m 4 ) s 5 Mc I Ê I 5 p 64 ( d 2 4 2 d 1 4 ) Ê d 2 5 d Ê d 1 5 d 2 2 t 5 4 5 d M max 5 W ¢ h 1 1 h 2 2 5 54.675 kN ? m t 5 d 10 Ê W 5 ph 2 ¢ b 2 5 8.1 kN (b) R EQUIRED DIAMETER BASED UPON SHEAR STRESS V max 5 W 5 8.1 kN 5 0.004059 m 2 d 5 0.06371 m 5 63.7 mm (Bending stress governs) d 2 5 7.0160 V max t allow 5 (7.0160)(8.1 kN)
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Unformatted text preview: 14 MPa t 5 4 V 3 ¢ 61 41 ≤ ¢ 100 9 p d 2 ≤ 5 7.0160 V d 2 A 5 p 4 ( d 2 2 1 d 1 2 ) 5 p 4 B d 2 2 ¢ 4 d 5 ≤ 2 R 5 9 p d 2 100 r 2 2 1 r 1 r 2 1 r 1 2 r 2 2 1 r 1 2 5 ¢ d 2 ≤ 2 1 ¢ d 2 ≤ ¢ 2 d 5 ≤ 1 ¢ 2 d 5 ≤ 2 ¢ d 2 ≤ 2 1 ¢ 2 d 5 ≤ 2 5 61 41 r 1 5 d 2 2 t 5 d 2 2 d 10 5 2 d 5 t 5 4 V 3 A ¢ r 2 2 1 r 1 r 2 1 r 1 2 r 2 2 1 r 1 2 ≤ Ê r 2 5 d 2 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

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