05-05ChapGere.0011

# 05-05ChapGere.0011 - d 1 5 200 mm Determine the allowable...

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Solution 5.12-5 Palm tree 360 CHAPTER 5 Stresses in Beams F REE - BODY DIAGRAM P 1 5 900 lb P 2 5 100 lb L 1 5 12 ft 5 144 in. L 2 5 30 ft 5 360 in. d 5 14 in. S 5 p d 3 32 5 269.39 in. 3 A 5 p d 2 4 5 153.94 in. 2 M 5 P 1 L 1 cos 60º 1 P 2 L 2 cos 60º 5 [(900 lb)(144 in.) 1 (100 lb)(360 in.)] cos 60º 5 82,800 lb-in. N 5 ( P 1 1 P 2 ) sin 60º 5 (1000 lb) sin 60º 5 866 lb M AXIMUM TENSILE STRESS 52 5.6 psi 1 307.4 psi 5 302 psi M AXIMUM COMPRESSIVE STRESS s c 52 5.6 psi 2 307.4 psi 52 313 psi s t 52 N A 1 M S 52 866 lb 153.94 in. 2 1 82,800 lb-in. 269.39 in. 3 b L 1 L 2 P 2 P 1 N V M Problem 5.12-6 A vertical pole of aluminum is fixed at the base and pulled at the top by a cable having a tensile force T (see figure). The cable is attached at the outer surface of the pole and makes an angle a 5 25° at the point of attachment. The pole has length L 5 2.0 m and a hollow circular cross section with outer diameter d 2 5 260 mm and inner diameter
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Unformatted text preview: d 1 5 200 mm. Determine the allowable tensile force T allow in the cable if the allowable compressive stress in the aluminum pole is 90 MPa. Solution 5.12-6 Aluminum pole L T d 2 d 1 d 2 a a 5 25º L 5 2.0 m d 2 5 260 mm d 1 5 200 mm ( s c ) allow 5 90 MPa C ROSS SECTION 5 145.778 3 10 2 6 m 4 A T THE BASE OF THE POLE N 5 T cos a 5 0.90631 T ( N , T 5 newtons) 5 0.11782 T 1 0.84524 T 5 0.96306 T ( M 5 newton meters) M 5 ( T cos a ) ¢ d 2 2 ≤ 1 ( T sin a )( L ) c 5 d 2 2 5 130 mm 5 0.13 m I 5 p 64 ( d 2 4 2 d 1 4 ) 5 145,778 3 10 3 mm 4 A 5 p 4 ( d 2 2 2 d 1 2 ) 5 21,677 mm 2 5 21.677 3 10 2 3 mm 2 L T sin a d 2 N V M T cos a A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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