05-06ChapGere.0008

05-06ChapGere.0008 - P 5 34,000 lb 5 34 k 10,000 5 2 P 3.38...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
370 CHAPTER 5 Stresses in Beams Problem 5.12-18 A short length of a C 8 3 11.5 channel is subjected to an axial compressive force P that has its line of action through the midpoint of the web of the channel (see figure). (a) Determine the equation of the neutral axis under this loading condition. (b) If the allowable stresses in tension and compression are 10,000 psi and 8,000 psi, respectively, find the maximum permissible load P max . Solution 5.12-18 Channel in compression C 8 3 11.5 A 5 3.38 in. 2 h 5 2.260 in. t w 5 0.220 in. I z 5 1.32 in. 4 c 1 5 0.571 in. c 2 5 1.689 in. E CCENTRICITY OF THE LOAD (a) L OCATION OF THE NEUTRAL AXIS 52 0.847 in. (b) M AXIMUM LOAD BASED UPON TENSILE STRESS s allow 5 10,000 psi ( P 5 pounds)
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: P 5 34,000 lb 5 34 k 10,000 5 2 P 3.38 1 P 1.695 5 0.2941 P 5 2 P 3.38 in. 2 1 P (0.461 in.)(1.689 in.) 1.32 in. 4 s t 5 2 P A 1 Pe c 2 I y 5 2 I Ae 5 2 1.32 in. 4 (3.38 in. 2 )(0.461 in.) e 5 c 1 2 t w 2 5 0.571 2 0.110 5 0.461 in. M AXIMUM LOAD BASED UPON COMPRESSIVE STRESS s allow 5 8000 psi ( P 5 pounds) P 5 16,200 lb 5 16.2 k C OMPRESSION GOVERNS . P max 5 16.2 k 8000 5 P 3.38 2 P 5.015 5 0.4953 P 5 2 P 3.38 in. 2 2 P (0.461 in.)(0.571 in.) 1.32 in. 4 s c 5 2 P A 2 Pe c 1 I C z y P 0.220 in. 3 c 1 c 2 2.260 in. C z y P C 8 × 11.5 3 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
View Full Document

  • Spring '08
  • Armanios
  • Compressive stress, neutral axis, maximum load, maximum permissible load, axial compressive force, in. tw c2

{[ snackBarMessage ]}

Ask a homework question - tutors are online